s_(n+1) = (s_n + r) / (s

s_(n+1) = (s_n + r) / (s_n + 1)

送交者: permutation 于 2009-01-07, 10:42:31:

回答: A math question - solution? 由 t1301520 于 2009-01-07, 06:38:43:

=>
s_(n+1) - sqrt(r) = (s_n - sqrt(r)) * (1 - sqrt(r))/(s_n + 1)

only need to prove s_n + 1 > sqrt(r) - 1 for large n
i.e. s_n - sqrt(r) > - 2 for large n