送交者: mangolasi 于 2006-3-04, 13:06:44:

回答: 不对。 由 jxh 于 2006-3-04, 12:42:03:

My outline of algorithm:

1)check the # of ways to divide 11 coins exactly the same into 4 groups:{11,0,0,0},{10,1,0,0} etc.

2)people are different, hence P(4,4) times the # of ways to divide coins.

write a formula later.

• 还有个问题，你没考虑到4 groups里面有两个或以上的group的硬币数目相同的情况 - deadmeat (70 bytes) 2006-3-04, 13:39:10
  • Indeed. - mangolasi (209 bytes) 2006-3-04, 13:45:25
• hmm, not a general formula yet, but for the first step: - mangolasi (545 bytes) 2006-3-04, 13:22:15
  • Forget to add a condtion of stopping taking: when the # you take - mangolasi (111 bytes) 2006-3-04, 13:28:05

加跟贴