送交者: mangolasi 于 2006-3-04, 13:45:25:
回答: 还有个问题，你没考虑到4 groups里面有两个或以上的group的硬币数目相同的情况 由 deadmeat 于 2006-3-04, 13:39:10:
So should it be: P(1,4) for {11,0,0,0}
P(2,4) those only take coins from 11 to fill one 0.
P(3,4) for those taking coins to fill 2 0.
P(4,4) for those taking coins to fill 3 0.
I declare to give up.