送交者: Palmetto 于 2009-10-29, 01:56:17:

回答: But v_j^2=V^2+(v_j-V)^2 is absurd and not needed 由 gyro 于 2009-10-29, 00:57:54:

• I never take the Berkeley "proof" seriously - gyro (151 bytes) 2009-10-29, 02:05:00 (378217)
  • 仅仅定义是不够的，因为v_j是变数，它们的合可能也是。 (无内容) - Palmetto (0 bytes) 2009-10-29, 02:43:54 (378225)

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