"大不了每点都证他收敛或不收敛"-the problem is that


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送交者: 2cents 于 2008-10-05, 20:48:30:

回答: 昏昏:不空的零测集本身不应构成困难,大不了每点都证他收敛或不收敛,为什么不管了? 由 短江学者 于 2008-10-05, 19:21:39:

a zero measure set still could have too many points -- could be inumerate number of points (i.e., more points than the number of rational numbers). For example, the Cantor set (http://en.wikipedia.org/wiki/Cantor_set). Therefore, it is impossible to 每点都证他收敛或不收敛

From what you wrote, I can tell that you were not a math major when you were in college. It is often funny (and a bit annoying) to read your posts. If you are really interested in math, it will be more useful to pick up a math text book to carefully study it.





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