1 + 3 * x + 8 * y

1 + 3 * x + 8 * y

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送交者: permutation 于 2008-02-12, 12:54:10:

回答: 1 + sum(n_i^2 - 1) 由 permutation 于 2008-02-12, 12:06:27:

since when n > 3, n^2 - 1 can be expressed as a combination of 3 and 8.

so any number except

2 3 5 6 11 14

6 can be done easily (无内容) - 008 (0 bytes) 2008-02-12, 12:59:32 (204711)
你几乎在那里了. (无内容) - smileykingkong (0 bytes) 2008-02-12, 12:58:01 (204708)