送交者: alexdongli 于 2006-2-24, 22:02:48:

回答: 做题 由 jxh 于 2006-2-24, 21:45:24:

The last two digits are 49. So 4+9 = 13.
Last 2 digits:
9^0 = 01
9^1 = 09
9^2 = 81
9^3 = 29
9^4 = 61
9^5 = 49
...
9^10= 01
9^11= 09
...
9^2005= 49.

• Your way worked well, but the anwer is 7. - jxh (0 bytes) 2006-2-25, 15:00:38
• better answer - alexdongli (118 bytes) 2006-2-24, 22:32:40
  • 只计算最后两项即可 - deadmeat (8 bytes) 2006-2-25, 06:59:35

加跟贴